Show graphically that each one of the following systems of equations has infinitely many solutions:
$x-2 y+11=0$
$3 x-6 y+33=0$
The given equations are
$x-2 y+11=0$ $\ldots \ldots \ldots(i)$
$3 x-6 y+33=0$(ii)
Putting $x=0$ in equation $(i)$, we get:
$\Rightarrow 0-2 y=-11$
$\Rightarrow y=11 / 2$
$x=0, \quad y=11 / 2$
Putting $y=0$ in equation $(i)$ we get:
$\Rightarrow x-2 \times=-11$
$\Rightarrow x=-11$
$x=-11, \quad y=0$
Use the following table to draw the graph.
Draw the graph by plotting the two points $A(0,11 / 2), B(-11,0)$ from table.
Graph of the equation….$(i i)$
$3 x-6 y=-33$....$(i i)$
Putting $x=0$ in equation (ii) we get:
$\Rightarrow 3 \times 0-6 y=-33$
$\Rightarrow y=11 / 2$
$x=0, \quad y=11 / 2$
Putting $y=0$ in equation $(i i)$, we get
$\Rightarrow 3 x-6 \times 0=-33$
$\Rightarrow x=-11$
$x=-11, \quad y=0$
Use the following table to draw the graph.
Draw the graph by plotting the two points $C(0,11 / 2), D(-11,0)$ from table.
Thus the graph of the two equations are coincide
Consequently, every solution of one equation is a solution of the other.
Hence the equations have infinitely many solutions.