Refer to Q.28. What is the probability that the card is

(i) Let $E_{3}=$ Event of getting a club

$n\left(E_{3}\right)=(13-3)=10$

$\therefore$ Required probability $=\frac{n\left(E_{3}\right)}{n(S)}=\frac{10}{49}$

(ii) Let $E_{4}=$ Event of getting 10 of hearts

$n\left(E_{4}\right)=1$

[because in 52 playing cards only 13 are the heart cards and only one10 in 13 heart cards]

$\therefore \quad$ Required probability $=\frac{n\left(E_{4}\right)}{n(S)}=\frac{1}{49}$