Question: Reaction of ammonia with excess $\mathrm{Cl}_{2}$ gives :
$\mathrm{NH}_{4} \mathrm{Cl}$ and $\mathrm{N}_{2}$
$\mathrm{NCl}_{3}$ and $\mathrm{NH}_{4} \mathrm{Cl}$
$\mathrm{NH}_{4} \mathrm{Cl}$ and $\mathrm{HCl}$
$\mathrm{NCl}_{3}$ and $\mathrm{HCl}$
Correct Option: , 4
Solution:
$\mathrm{NH}_{3}+\underset{\text { excess }}{3 \mathrm{Cl}_{2}} \longrightarrow \mathrm{NCl}_{3}+3 \mathrm{HCl}$
