Ravish wanted to make a temporary shelter for his car by making a box-like structure with the tarpaulin that covers all the four sides and the top of the car ( with the front face of a flap which can be rolled up).
Question:
Ravish wanted to make a temporary shelter for his car by making a box-like structure with the tarpaulin that covers all the four sides and the top of the car ( with the front face of a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how many tarpaulins would be required to make the shelter of height 2.5 m with base dimensions 4 m × 3m?
Solution:
Given That,
Shelter length = 4 m
Breadth = 3 m
Height = 2.5 m
The tarpaulin will be required for top and four sides of the shelter.
The Area of tarpaulin required = 2h(l + b) + lb
⇒ 2∗2.5 (4 + 3) + 4∗3
⇒ 5(7) + 12
$\Rightarrow 47 \mathrm{~m}^{2}$