Question: $\lim _{x \rightarrow 0} \frac{\int_{0}^{x^{2}}(\sin \sqrt{t}) d t}{x^{3}}$ is equal to:
(1) $\frac{2}{3}$
(2) 0
(3) $\frac{1}{15}$
(4) $\frac{3}{2}$
Correct Option: 1
Solution:
$\lim _{x \rightarrow 0} \frac{\int_{0}^{x^{2}} \sin \sqrt{t} d t}{x^{3}}$
