Question:
Given $: f(x)=\left\{\begin{array}{cc}x & 0 \leq x<\frac{1}{2} \\ \frac{1}{2} & x=\frac{1}{2} \\ 1-x & , \quad \frac{1}{2} and $g(x)=\left(x-\frac{1}{2}\right)^{2}, x \in R$. Then the area (in sq. units) of the region bounded by the curves, $\mathrm{y}=f(\mathrm{x})$ and $\mathrm{y}=\mathrm{g}(\mathrm{x})$ between the lines, $2 \mathrm{x}=1$ and $2 \mathrm{x}=\sqrt{3}$, is :
Correct Option: , 2
Solution:
