If $x / y$ is the additive inverse of $c / d$, then $(x / y)+(c / d)=0$
True.
Let $x / y=1 / 2$ and its additive inverse $c / d=-1 / 2$
Then, $(x / y)+(c / d)$
$=1 / 2+(-1 / 2)$
$=1 / 2-1 / 2$
$=0$
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