If $f^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2} $f(0)=0$, then $f(1)$ is equal to :
$f(0)=0$, then $f(1)$ is equal to :
$\frac{\pi-1}{4}$
$\frac{\pi+2}{4}$
$\frac{\pi+1}{4}$
$\frac{1}{4}$
Correct Option: , 3
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