Question: Two capacitors $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ are charged to $120 \mathrm{~V}$ and $200 \mathrm{~V}$ respectively. It is found that by connecting them together the potential on each one can be made zero. Then :
$5 \mathrm{C}_{1}=3 \mathrm{C}_{2}$
$3 \mathrm{C}_{1}=5 \mathrm{C}_{2}$
$3 \mathrm{C}_{1}+5 \mathrm{C}_{2}=0$
$9 C_{1}=4 C_{2}$
Correct Option: , 2
Solution:
