Prove that the function $f$ given by $f(x)=x^{2}-x+1$ is neither strictly increasing nor strictly decreasing on $(-1,1)$.
The given function is $f(x)=x^{2}-x+1$.
$\therefore f^{\prime}(x)=2 x-1$
Now, $f^{\prime}(x)=0 \Rightarrow x=\frac{1}{2}$.
The point $\frac{1}{2}$ divides the interval $(-1,1)$ into two disjoint intervals i.e., $\left(-1, \frac{1}{2}\right)$ and $\left(\frac{1}{2}, 1\right)$.
Now, in interval $\left(-1, \frac{1}{2}\right), f^{\prime}(x)=2 x-1<0$.
Therefore, $f$ is strictly decreasing in interval $\left(-1, \frac{1}{2}\right)$.
However, in interval $\left(\frac{1}{2}, 1\right), f^{\prime}(x)=2 x-1>0$.
Therefore, $f$ is strictly increasing in interval $\left(\frac{1}{2}, 1\right)$.
Hence, $f$ is neither strictly increasing nor decreasing in interval $(-1,1)$.