Question: $\sqrt[3]{8+27}=\sqrt[3]{8}+\sqrt[3]{27}$
Solution:
False
We have, $\sqrt[3]{8+27} \neq \sqrt[3]{8}+\sqrt[3]{27}$
$\because$ $\sqrt[3]{8}+\sqrt[3]{27}=\sqrt[3]{2 \times 2 \times 2}+\sqrt[3]{3 \times 3 \times 3}=2+3=5$
But $\sqrt[3]{8+27}=\sqrt[3]{35} \neq \sqrt[3]{125}=5$
