Question:
If $\frac{4}{5}, a, 2$ are three consecutive terms of an $\mathrm{AP}$, find the value of $a$.
Solution:
If $\frac{4}{5}, a$ and 2 are three consecutive terms of an $\mathrm{AP}$, then we have:
$a-\frac{4}{5}=2-a$
$\Rightarrow 2 a=2+\frac{4}{5}$
$\Rightarrow 2 a=\frac{14}{5}$
$\Rightarrow a=\frac{7}{5}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.