The function $F(x) \frac{9 x}{5}=+32$ is the formula to convert $\mathbf{x}^{\circ} \mathbf{C}$ to Fahrenheit units. \
Find
(i) $F(0)$,
(ii) $F(-10)$,
(iii) The value of $x$ when $f(x)=212$.
Interpret the result in each case.
Given: $\mathrm{F}(\mathrm{x})=\frac{9}{5} \mathrm{x}+32$ ....(i)
To find: (i) F(0)
Substituting the value of x = 0 in eq. (i), we get
$\mathrm{F}(\mathrm{x})=\frac{9}{5} \mathrm{x}+32$
$\Rightarrow \mathrm{F}(0)=\frac{9}{5} \times 0+32$
$\Rightarrow \mathrm{F}(0)=32$
It means $0^{\circ} \mathrm{C}=32^{\circ} \mathrm{F}$
To find: (ii) $F(-10)$
Substituting the value of $x=-10$ in eq. (i), we get
$\mathrm{F}(\mathrm{x})=\frac{9}{5} \mathrm{x}+32$
$\Rightarrow \mathrm{F}(-10)=\frac{9}{5} \times(-10)+32$
$\Rightarrow \mathrm{F}(-10)=9 \times(-2)+32$
$\Rightarrow \mathrm{F}(-10)=-18+32$
$\Rightarrow \mathrm{f}(-10)=14$
It means $-10^{\circ} \mathrm{C}=14^{\circ} \mathrm{F}$
To find: (iii) the value of $x$ when $F(x)=212$
It is given that $\mathrm{F}(\mathrm{x})=\frac{9}{5} \mathrm{x}+32$
Substituting the value of F(x) = 212 in the above equation, we get
$212=\frac{9}{5} x+32$
$\Rightarrow 212-32=\frac{9}{5} \mathrm{x}$
$\Rightarrow 180=\frac{9}{5} \mathrm{x}$
$\Rightarrow \mathrm{x}=180 \times \frac{5}{9}$
$\Rightarrow \mathrm{x}=20 \times 5$
$\Rightarrow \mathrm{x}=100$
It means $212^{\circ} \mathrm{F}=100^{\circ} \mathrm{C}$