prove that

Given,  $\frac{3 x-8}{2 x}=1$

$\Rightarrow$ $3 x-8=2 x$ [bycross-multiplication]

$\Rightarrow \quad 3 x-2 x=8 \quad$ [transposing $2 x$ to LHS and 8 to RHS]

$\therefore$ $x=8$