Question:
$e^{2 x+3}$
Solution:
Let $2 x+3=t$
$\therefore 2 d x=d t$
$\Rightarrow \int e^{2 x+3} d x=\frac{1}{2} \int e^{t} d t$
$=\frac{1}{2}\left(e^{t}\right)+\mathrm{C}$
$=\frac{1}{2} e^{(2 x+3)}+\mathrm{C}$
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