Question:
Product of 6a2 – 7b + 5ab and 2ab is
(a) 12a3b – 14ab2 + 10ab
(b) 12a3b – 14ab2 + 10a2b2
(c) 6a2 – 7b + 7ab
(d) 12a2b – 7ab2 + 10ab
Solution:
(b) 12a3b – 14ab2 + 10a2b2
Now we have find product of trinomial and monomial,
= (6a2 – 7b + 5ab) × 2ab
= (2ab × 6a2) – (2ab × 7b) + (2ab × 5ab)
= 12a3b – 14ab2 + 10a2b2