Question.
Pressure is determined as force per unit area of the surface. The SI unit of pressure, Pascal is as shown below
$1 \mathrm{~Pa}=1 \mathrm{~N} \mathrm{~m}^{-2}$
If mass of air at sea level is $1034 \mathrm{~g} \mathrm{~cm}^{-2}$, calculate the pressure in Pascal.
Pressure is determined as force per unit area of the surface. The SI unit of pressure, Pascal is as shown below
$1 \mathrm{~Pa}=1 \mathrm{~N} \mathrm{~m}^{-2}$
If mass of air at sea level is $1034 \mathrm{~g} \mathrm{~cm}^{-2}$, calculate the pressure in Pascal.
Solution:
Pressure is defined as force acting per unit area of the surface.
$=1.01332 \times 10^{5} \mathrm{~kg} \mathrm{~m}^{-1} \mathrm{~s}^{-2}$
We know
$1 \mathrm{~N}=1 \mathrm{~kg} \mathrm{~ms}^{-2}$
Then
$1 \mathrm{~Pa}=1 \mathrm{Nm}^{-2}=1 \mathrm{~kg} \mathrm{~m}^{-2} \mathrm{~s}^{-2} 1$
$P a=1 \mathrm{~kg} m^{-1} s^{-2}$
$\therefore$ Pressure $=1.01332 \times 10^{5} \mathrm{~Pa}$
Pressure is defined as force acting per unit area of the surface.
$=1.01332 \times 10^{5} \mathrm{~kg} \mathrm{~m}^{-1} \mathrm{~s}^{-2}$
We know
$1 \mathrm{~N}=1 \mathrm{~kg} \mathrm{~ms}^{-2}$
Then
$1 \mathrm{~Pa}=1 \mathrm{Nm}^{-2}=1 \mathrm{~kg} \mathrm{~m}^{-2} \mathrm{~s}^{-2} 1$
$P a=1 \mathrm{~kg} m^{-1} s^{-2}$
$\therefore$ Pressure $=1.01332 \times 10^{5} \mathrm{~Pa}$