Question:
Oxidation number of potassium in $\mathrm{K}_{2} \mathrm{O}, \mathrm{K}_{2} \mathrm{O}_{2}$ and $\mathrm{KO}_{2}$, respectively, is:
Correct Option: , 2
Solution:
$\mathrm{K}_{2} \mathrm{O}: 2 x-2=0 \Rightarrow x=+1$
$\mathrm{~K}_{2} \mathrm{O}_{2}: 2 x-2=0 \Rightarrow x=+1$
$\mathrm{KO}_{2}: x-1=0 \Rightarrow x=+1$
Thus, potassium shows $+1$ state in all its oxides, superoxides and peroxides.