Outermost electronic configuration of a group 13 element,

Question:

Outermost electronic configuration of a group 13 element, $E$, is $4 \mathrm{~s}^{2}, 4 \mathrm{p}^{1}$. The electronic configuration of an element of p-block period-five placed diagonally to element, $\mathrm{E}$ is :

  1. [Kr] $3 \mathrm{~d}^{10} 4 \mathrm{~s}^{2} 4 \mathrm{p}^{2}$

  2. $[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{2} 4 \mathrm{p}^{2}$

  3. $[\mathrm{Xe}] 5 \mathrm{~d}^{10} 6 \mathrm{~s}^{2} 6 \mathrm{p}^{2}$

  4. $[\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^{2} 5 \mathrm{p}^{2}$

Correct Option: , 4

Solution:

The element E is Ga and the diagonal element of $5^{\text {th }}$ period is ${ }_{50} \mathrm{Sn}$ having outer electronic configuration will be $[\mathrm{Kr}] 5 \mathrm{~s}^{2} 4 \mathrm{~d}^{10} 5 \mathrm{p}^{2}$

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