Question:
onstruct a quadrilateral ABCD given that AB = 4 cm, BC = 3 cm, ∠A = 75°, ∠B = 80° and ∠C = 120°.
Solution:
Steps of construction:
Step I: Draw $\mathrm{AB}=4 \mathrm{~cm} .$
Step II : Construct $\angle \mathrm{XAB}=75^{\circ}$ at $\mathrm{A}$ and $\angle \mathrm{ABY}=80^{\circ}$ at B.
Step III : With B as the centre and radius $3 \mathrm{~cm}$, cut off BC $=3 \mathrm{~cm} .$
Step IV : At C, draw $\angle \mathrm{BCZ}=120^{\circ}$ such that it meets AX at D.
The quadrilateral so obtained is the required quadrilateral.
.png)