Question:
One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number which is a multiple
of 5 is
(a) $\frac{1}{5}$
(b) $\frac{3}{5}$
(c) $\frac{4}{5}$
(d) $\frac{1}{3}$
Solution:
(a) Number of total outcomes = 40
Multiples of 5 between 1 to 40 = 5,10,15,20,25. 30 35, 40
$\therefore$ Total number of possible outcomes $=8$
$\therefore$ Required probability $=\frac{8}{40}=\frac{1}{5}$