Question:
On dividing p (4p2 – 16) by 4p (p – 2), we get
(a) 2p + 4
(b) 2p – 4
(c) p + 2
(d) p – 2
Solution:
(c) p + 2
On dividing p (4p2 – 16) by 4p (p – 2)
= (p((2p)2 – (4)2))/ (4p(p – 2))
= ((2p – 4) × (2p + 4))/(4(p – 2))
Take out the common factors
= ((2(p – 2)) × (2 (p + 4)))/(4(p -2))
= (4(p – 2)(p + 2))/ (4(p – 2))
= p + 2