Question:
Negation of the statement:
$\sqrt{5}$ is an integer of 5 is irrational is:
Correct Option: , 2
Solution:
Let $\mathrm{p}$ and $\mathrm{q}$ the statements such that $p=\sqrt{5}$ is an integer $q=5$ is an irrational number.
Then, negation of the given statement
$\sqrt{5}$ is not an integer and 5 is not an irrational Number
$\sim(p \vee q)=\sim p \wedge \sim q$