Question: Evaluate:
$\sqrt[3]{\frac{-64}{343}}$
Solution:
$\sqrt[3]{\frac{-64}{343}}$
On factorisation:
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$\sqrt[3]{\frac{64}{343}}=\sqrt[3]{\frac{2 \times 2 \times 2 \times 2 \times 2 \times 2}{7 \times 7 \times 7}}$
$\therefore \sqrt[3]{\frac{-64}{343}}=\frac{-4}{7}$
