In ΔABC and ΔDEF, AB = FD and ∠A = ∠D.

Question:

In ΔABC and ΔDEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom, if

(a) BC = EF            

(b) AC = DE                  

(c)AC=EF                    

(d) BC = DE

Solution:

(b) Given, in ΔABC and ΔDEF, AB = DF and ∠A = ∠D

We know that, two triangles will be congruent by ASA rule, if two angles and the included side of one triangle are equal to the two angles and the

included side of other triangle.

∴ AC = DE

Leave a comment