The value of $\lim _{x \rightarrow 0}\left(\frac{x}{\sqrt[8]{1-\sin x}-\sqrt[8]{1+\sin x}}\right)$ is equal
to:
Correct Option: 3,
$\lim _{x \rightarrow 0}\left(\frac{x}{\sqrt[8]{1-\sin x}-\sqrt[8]{1+\sin x}}\right)$
$=\lim _{x \rightarrow 0}\left(\frac{x}{\sqrt[8]{1-\sin x}-\sqrt[8]{1+\sin x}}\right)$
$=\lim _{x \rightarrow 0}\left(\frac{x}{\sqrt[8]{1-\sin x}-\sqrt[8]{1+\sin x}}\right)$
$\left(\frac{(\sqrt[8]{1-\sin x}+\sqrt[8]{1+\sin x})}{\sqrt[8]{1-\sin x}+\sqrt[8]{1+\sin x}}\right)$
$\left(\frac{(\sqrt[4]{1-\sin x}+\sqrt[4]{1+\sin x})}{\sqrt[4]{1-\sin x}+\sqrt[4]{1+\sin x}}\right)$
$\left(\frac{(\sqrt[2]{1-\sin x}+\sqrt[2]{1+\sin x})}{\sqrt[2]{1-\sin x}+\sqrt[2]{1+\sin x}}\right)$
$=\lim _{x \rightarrow 0}\left(\frac{x}{1-\sin x-(1+\sin x)}\right)$
$(\sqrt[8]{1-\sin x}+\sqrt[8]{1+\sin x})(\sqrt[4]{1-\sin x}+\sqrt[4]{1+\sin x})$
$(\sqrt[2]{1-\sin x}+\sqrt[2]{1+\sin x})$
$=\lim _{x \rightarrow 0} \frac{x}{(-2 \sin x)}(\sqrt[8]{1-\sin x}+\sqrt[8]{1+\sin x})$
$(\sqrt[4]{1-\sin x}+\sqrt[4]{1+\sin x})(\sqrt[2]{1-\sin x}+\sqrt[2]{1+\sin x})$
$=\lim _{x \rightarrow 0}\left(-\frac{1}{2}\right)(2)(2)(2)\left\{\because \lim _{x \rightarrow 0} \frac{\sin x}{x}=1\right\}=-4$
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