Question: If $f: R^{+} \rightarrow R$ is defined as $f(x)=\log _{3} x$, then $r^{-1}(x)=$
Solution:
Given: f(x) = log3x
$f(x)=\log _{3} x$
$\Rightarrow y=\log _{3} x$
$\Rightarrow x=3^{y}$
Thus, $f^{-1}(y)=3^{y}$.
Hence, $f^{-1}(x)=\underline{3}^{x}$.
