Question:
Monu's father is 26 years younger than Monu's grandfather and 29 years older than Monu. The sum of the ages of all the three is 135 years. What is the age of each one of them?
Solution:
Let the age of Monu's father be x years.
The age of Monu's grandfather will be $(x+26)$.
Then, the age of Monu will be $(\mathrm{x}-29)$.
$\therefore x+(x+26)+(x-29)=135$
$\Rightarrow x+x+26+x-29=135$
$\Rightarrow 3 x-3=135$
$\Rightarrow 3 x=135+3$
$\Rightarrow 3 x=138$
$\Rightarrow x=\frac{138}{3}=46$
$\therefore A$ ge of Monu's father $=46$ years
Age of Monu's grandfather $=(\mathrm{x}+26)=(46+26)=72$ years
Age of Monu $=(\mathrm{x}-29)=46-29=17$ years