Question:
MnO42- undergoes disproportionation reaction in acidic medium but MnO4–
does not. Give reason.
Solution:
In – MnO4, Mn is in the highest oxidation state i.e. +7. Therefore, it does
not undergo disproportionation. MnO42– undergoes disproportionation
as follows :
3MnO42– + 4H+ → 2MnO4– + MnO2+ 2H2O