Maximise

Question:

Maximise $Z=3 x+2 y$

subject to $x+2 y \leq 10,3 x+y \leq 15, x, y \geq 0$.

Solution:

The feasible region determined by the constraints, $x+2 y \leq 10,3 x+y \leq 15, x \geq 0$, and $y \geq 0$, is as follows.

The corner points of the feasible region are A (5, 0), B (4, 3), and C (0, 5).

The values of Z at these corner points are as follows.

Therefore, the maximum value of Z is 18 at the point (4, 3).

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now