Question:
Mark the correct alternative in each of the following:
A die is thrown once. The probability of getting a prime number is
(a) $\frac{2}{3}$
(b) $\frac{1}{3}$
(c) $\frac{1}{2}$
(d) $\frac{1}{6}$ [CBSE 2013]
Solution:
In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.
∴ Total number of outcomes = 6
The favourable outcomes are 2, 3 and 5.
So, the number of favourable outcomes are 3.
$\therefore \mathrm{P}($ getting a prime number $)=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{3}{6}=\frac{1}{2}$
Hence, the correct answer is option C.