Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
The general solution of the $D E \log \left(\frac{d y}{d x}\right)=(a x+b y)$ is
A. $\frac{-e^{-b y}}{b}=\frac{e^{a x}}{a}+C$
B. $e^{a x}-e^{-b y}=C$
C. $b e^{a x}+a e^{b y}=C$
D. None of these
Solution:
