Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
The solution of the $\mathrm{DE} \frac{\mathrm{dy}}{\mathrm{dx}}=1-x+y-x y$ is
A. $\log (1+y)=x-\frac{x^{2}}{2}+C$
B. $e^{(1+y)}=x-\frac{x^{2}}{2}+C$
C. $\mathrm{e}^{\mathrm{y}}=\mathrm{x}-\frac{\mathrm{x}^{2}}{2}+\mathrm{C}$
D. None of these
Solution:
