Question:
Mark against the correct answer in each of the following:
If the line $\frac{x+1}{3}=\frac{y-2}{4}=\frac{z+6}{5}$ is parallel to the plane $2 x-3 y+k z=0$, then the value of $k$ is
A. $\frac{5}{6}$
B. $\frac{6}{5}$
C. $\frac{3}{4}$
D. $\frac{4}{5}$
Solution:
