Question:
Mark $(\sqrt{)}$ against the correct answer in each of the following:
If $\vec{a}$ and $\vec{b}$ are two vectors such that $|\vec{a}|=|\vec{b}|=\sqrt{2}$ and $\vec{a} \cdot \vec{b}=-1$ then the angle between
$\vec{a}$ and $\vec{b}$ is
A. $\frac{\pi}{6}$
B. $\frac{\pi}{4}$
C. $\frac{\pi}{3}$
D. $\frac{2 \pi}{3}$
Solution:
