Question:
Mark (✓) against the correct answer:
A can do a piece of work in 14 days and B is 40% more efficient than A. In how many days can B finish it?
(a) 10 days
(b) $7 \frac{1}{2}$ days
(c) $5 \frac{1}{4}$ days
(d) $5 \frac{3}{5}$ days
Solution:
(a) 10 days
A's 1 day work $=\frac{1}{14}$
B is $40 \%$ more efficient than A.
$\therefore$ B's 1 day work $=\frac{140}{100} \times \frac{1}{14}=\frac{1}{10}$
B takes 10 days to complete the work.