Question:
Mark (✓) against the correct answer
What should be added to $\frac{-3}{5}$ to get $\frac{-1}{3} ?$
(a) $\frac{4}{5}$
(b) $\frac{8}{15}$
(c) $\frac{4}{15}$
(d) $\frac{2}{5}$
Solution:
(C) $\frac{4}{15}$
Let the number be
Now,
$\frac{-3}{5}+x=\frac{-1}{3}$
$\Rightarrow x=\frac{-1}{3}+\left(\right.$ Additive inverse of $\left.\frac{-3}{5}\right)$
$\Rightarrow x=\frac{-1}{3}+\frac{3}{5}$
$\Rightarrow x=\left(\frac{-1 \times 5}{3 \times 5}\right)+\left(\frac{3 \times 3}{5 \times 3}\right)$
$\Rightarrow x=\frac{-5}{15}+\frac{9}{15}$
$\Rightarrow x=\frac{-5+9}{15}$
$\Rightarrow x=\frac{4}{15}$