Question:
Mark (✓) against the correct answer:
In a square PQRS, if PQ = (2x + 3) cm and QR = (3x − 5) cm then
(a) x = 4
(b) x = 5
(c) x = 6
(d) x = 8
Solution:
(d) x = 8
All sides of a square are equal..png)
$P Q=Q R$
$(2 x+3)=(3 x-5)$
$=>2 x-3 x=-5-3$
$=>x=8 \mathrm{~cm}$