Making use of the cube root table, find the cube root 7800

We have:

$7800=78 \times 100$

$\therefore \sqrt[3]{7800}=\sqrt[3]{78 \times 100}=\sqrt[3]{78} \times \sqrt[3]{100}$

By the cube root table, we have:

$\sqrt[3]{78}=4.273$ and $\sqrt[3]{100}=4.642$

$\sqrt[3]{7800}=\sqrt[3]{78} \times \sqrt[3]{100}=4.273 \times 4.642=19.835$ (upto three decimal places)

Thus, the answer is 19.835