Question:
Make the correct alternative in the following question:
Let P(n): 2n < (1 × 2 × 3 × ... × n). Then the smallest positive integer for which P(n) is true
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
As, 2n < (1 × 2 × 3 × ... × n) is possible only when n
So, the smallest positive integer for which P(n) is true, is 4.
Hence, the correct alternative is option (d).