Let Z be the set of integers. Show that the relation
R = {(a, b) : a, b ∈ Z and a + b is even}
is an equivalence relation on Z.
We observe the following properties of R.
Reflexivity:
Let $a$ be an arbitrary element of $Z$. Then,
$a \in R$
Clearly, $a+a=2 a$ is even for all $a \in Z$.
$\Rightarrow(a, a) \in R$ for all $a \in Z$
So, $R$ is reflexive on $Z$.
Symmetry:
Let $(a, b) \in R$
$\Rightarrow a+b$ is even
$\Rightarrow b+a$ is even
$\Rightarrow(b, a) \in R$ for all $a, b \in Z$
So, $R$ is symmetric on $Z$.
Transitivity:
Let $(a, b)$ and $(b, c) \in R$
$\Rightarrow a+b$ and $b+c$ are even
Now, let $a+b=2 x$ for some $x \in Z$
and $b+c=2 y$ for some $y \in Z$
Adding the above two, we get
$a+2 b+c=2 x+2 y$
$\Rightarrow a+c=2(x+y-b)$, which is even for all $x, y, b \in Z$
Thus, $(a, c) \in R$
So, $R$ is transitive on $Z$.
Hence, R is an equivalence relation on Z