Let X represents the difference between the number of heads and the number of tails obtained when a coin is tossed 6 times.

A coin is tossed six times and X represents the difference between the number of heads and the number of tails.

$\therefore \mathrm{X}(6 \mathrm{H}, 0 \mathrm{~T})=|6-0|=6$

$X(5 H, 1 T)=|5-1|=4$

$X(4 \mathrm{H}, 2 T)=|4-2|=2$

$X(3 H, 3 T)=|3-3|=0$

$X(2 H, 4 T)=|2-4|=2$

$X(1 \mathrm{H}, 5 \mathrm{~T})=|1-5|=4$

$\mathrm{X}(\mathrm{OH}, 6 \mathrm{~T})=|0-6|=6$

Thus, the possible values of X are 6, 4, 2, and 0.