Question:
Let R be a relation on the set N given by
R = {(a, b) : a = b − 2, b > 6}. Then,
(a) $(2,4) \in R$
(b) $(3,8) \in R$
(c) $(6,8) \in R$
(d) $(8,7) \in R$
Solution:
(c) $(6,8) \in R$
$(6,8) \in R$
Then,
$a=b-2$
$\Rightarrow 6=8-2$
and $b=8>6$
Henc $e,(6,8) \in R$