Question: Let $R$ be a relation in $N$ defined by $R=\{(x, y): x+2 y=8\}$, then the range of $R$ is
Solution:
Given: R = {(x, y): x + 2y = 8} where x, y ∈ N
R = {(6, 1), (4, 2), (2, 3)}
Therefore, Range of R = {1, 2, 3}
Hence, the range of R is {1, 2, 3}.
