Question:
Let $\mathrm{P}$ be the point on the parabola, $\mathrm{y}^{2}=8 \mathrm{x}$ which is at a minimum distance from the cente $\mathrm{C}$ of the circle, $\mathrm{x}^{2}+(\mathrm{y}+6)^{2}=1$. Then the equation of the circle, passing through $\mathrm{C}$ and having its centre at $\mathrm{P}$ is :
Correct Option: , 2
Solution:
