Question:
Let $\mathrm{f}$ be a function defined by $\mathrm{f}(\mathrm{x})=(\mathrm{x}-1)^{2}+1,(\mathrm{x} \geq 1)$
Statement - 1 : The set $\left\{x: f(x)=f^{-1}(x)\right\}=\{1,2\}$
Statement - 2 : $f$ is bijection and $\mathrm{f}^{-1}(\mathrm{x})=1+\sqrt{\mathrm{x}-1}, \mathrm{x} \geq 1$
Correct Option: , 3
Solution:
