Let $a_{1}, a_{2}, a_{3}, \ldots$ be a G.P. such that $a_{1}<0$,
$a_{1}+a_{2}=4$ and $a_{3}+a_{4}=16 .$ If $\sum_{i=1}^{9} a_{1}=4 \lambda$, then $\lambda$ is equal to :
$-171$
171
$\frac{511}{3}$
$-513$
Correct Option: 1
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