It is known that for a given mass of gas, the volume v varies inversely as the pressure p. Fill in the missing entries in the following table:
Since the volume and pressure for the given mass vary inversely, we have:
$v p=k$
For $v=60$ and $p=\frac{3}{2}$, we have :
$k=60 \times \frac{3}{2}$
$=90$
For $p=2$ and $k=90$, we have :
$2 v=90$
$\Rightarrow v=\frac{90}{2}$
$=45$
For $v=48$ and $k=90$, we have :
$48 p=90$
$\Rightarrow p=\frac{90}{48}$
$=\frac{15}{8}$
For $p=1$ and $k=90$, we have :
$1 v=90$
$\Rightarrow v=\frac{90}{1}$
$=90$
For $v=100$ and $k=90$, we have :
$100 p=90$
$\Rightarrow v=\frac{90}{100}$
$=\frac{9}{10}$
For $p=\frac{1}{2}$ and $k=90$, we have :
$\frac{1}{2} v=90$
$\Rightarrow v=90 \times 2$
$=180$
For $v=200$ and $k=90$, we have :
$200 p=90$
$\Rightarrow p=\frac{90}{200}$
$=\frac{9}{20}$