It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.
Question:
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?
Solution:
Probability that two students are not having same birthday $P(\overline{\mathrm{E}})=0.992$
Probability that two students are having same birthday $P(E)=1-P(\bar{E})$
$=1-0.992$
$=0.008$