Question.
Is it possible to design a rectangular mango grove whose length is twice its breadth, and area is $800 \mathrm{~m}^{2}$ ? If so, find its length and breadth.
Is it possible to design a rectangular mango grove whose length is twice its breadth, and area is $800 \mathrm{~m}^{2}$ ? If so, find its length and breadth.
Solution:
Let x be the breadth and 2x be the length of the rectangle.
$x \times 2 x=800$
$\Rightarrow 2 x^{2}=800$
$\Rightarrow x^{2}=400=(20)^{2}$
$\Rightarrow x=20$
Hence, the rectangle is possible and it has breadth $=20 \mathrm{~m}$ and length $=40 \mathrm{~m}$.
Let x be the breadth and 2x be the length of the rectangle.
$x \times 2 x=800$
$\Rightarrow 2 x^{2}=800$
$\Rightarrow x^{2}=400=(20)^{2}$
$\Rightarrow x=20$
Hence, the rectangle is possible and it has breadth $=20 \mathrm{~m}$ and length $=40 \mathrm{~m}$.